How do we consider a Gaussian surface perfectly in order to avoid integration?
A point charge causes an electric flux of –1.0×103Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
What is the value of the point charge?
Figure 20.17 shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to
