266
Question
How to prove dimensions for the equation v2=u2+2ax
How to prove dimensions for the equation v2=u2+2ax
Open in App
Solution
We can check the correctness of equation by Dimensional Analysis.
Equation: V²=U²-2as
where V=u=velocities = Dimension=LT⁻¹
a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²
S=Distance=L
R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]
Dimension of L.H.S=[v²] =[u²] =[LT⁻¹]²=[L²T⁻²]
Therefore L.H.S=R.H.S
Hence we can say equation is correct
Equation: V²=U²-2as
where V=u=velocities = Dimension=LT⁻¹
a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²
S=Distance=L
R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]
Dimension of L.H.S=[v²] =[u²] =[LT⁻¹]²=[L²T⁻²]
Therefore L.H.S=R.H.S
Hence we can say equation is correct
Suggest Corrections
37
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
