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Byju's Answer

Standard VI

Mathematics

Addition of Integers by Forming Pairs

How to solve ...

Question

How to solve
(_-1+2-3+4-5+6-7+8-9+10

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Solution

-1+2-3+4-5+6-7+8-9+10 = 1-3+4-5+6-7+8-9+10
= -2+4-5+6-7+8-9+10
= 2-5+6-7+8-9+10
= -3+6-7+8-9+10
= 3-7+8-9+10
= -4+8-9+10
= 4-9+10
= -5+10
= 5
general formula => sum= n = number of even numbers = number of odd numbers
here it is = 5

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Similar questions

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

Q. Solve the following equations.
(1) 17p − 2 = 49
(2) 2m + 7 = 9
(3) 3x + 12 = 2x − 4
(4) 5(x − 3) = 3(x + 2)

(5)

\frac{9 x}{8}

+ 1 = 10

(6)

\frac{y}{7}

\frac{y - 4}{3}

= 2

(7) 13x − 5 =

\frac{3}{2}

(8) 3(y + 8) = 10(y − 4) + 8

(9)

\frac{x - 9}{x - 5}

\frac{5}{7}

(10)

\frac{y - 4}{3}

+ 3y = 4

(11)

\frac{b + (b + 1) + (b + 2)}{4}

= 21

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

Q. Find the values of the following:

(1) 11³
(2) (–5)²
(3) (–3)³
(4) 10⁷
(5) 2⁴
(6)

{(\frac{2}{3})}^{5}

(7)

{(- \frac{1}{5})}^{4}

(8) 2⁸
(9) (–1)⁸
(10) (–1)⁹

In a Mathematics test, the following marks were obtained by 40 students. Arrange these marks in a table using tally marks.

8	1	3	7	6	5	5	4	4	2
4	9	5	3	7	1	6	5	2	7
7	3	8	4	2	8	9	5	8	6
7	4	5	6	9	6	4	4	6	6

(a) Find how many students obtained marks equal to or more than7.

(b) How many students obtained marks below 4?

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How to solve (_-1+2-3+4-5+6-7+8-9+10

-1+2-3+4-5+6-7+8-9+10 = 1-3+4-5+6-7+8-9+10 = -2+4-5+6-7+8-9+10 = 2-5+6-7+8-9+10 = -3+6-7+8-9+10 = 3-7+8-9+10 = -4+8-9+10 = 4-9+10 = -5+10 = 5 general formula => sum= n = number of even numbers = number of odd numbers here it is = 5

How to solve
(_-1+2-3+4-5+6-7+8-9+10

-1+2-3+4-5+6-7+8-9+10 = 1-3+4-5+6-7+8-9+10
= -2+4-5+6-7+8-9+10
= 2-5+6-7+8-9+10
= -3+6-7+8-9+10
= 3-7+8-9+10
= -4+8-9+10
= 4-9+10
= -5+10
= 5
general formula => sum= n = number of even numbers = number of odd numbers
here it is = 5