Question

How to solve $26\times \left(-48\right)+\left(-48\right)\times \left(-36\right)$.

Answer 1

Finding the solution:

Given: $26\times \left(-48\right)+\left(-48\right)\times \left(-36\right)$

That is

$26\times \left(-48\right)+\left(-48\right)\times \left(-36\right)$

$$\begin{gathered} =48\left[26\times \left(-1\right)+\left(-1\right)\times \left(-36\right)\right] \\ =48\left[-26+36\right] \\ =48\left[10\right] \\ =480 \end{gathered}$$

Hence, the required value is $480$.