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Question

How to solve a chemical equations and how to balanced a chemical equation with some examples.Step by step.In each step with some hard equations????? Please

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Solution

- C
_{3}H_{8}+ O_{2}--> H_{2}O + CO_{2} - This reaction occurs when propane (C
_{3}H_{8}) is burned in the presence of oxygen to produce water and carbon dioxide.

- Left side: 3 carbon, 8 hydrogen and 2 oxygen.
- Right side: 1 carbon, 2 hydrogen and 3 oxygen.

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- C
_{3}H_{8}+ O_{2}--> H_{2}O + 3CO_{2} - The coefficient 3 in front of carbon on the right side indicates 3 carbon atoms just as the subscript 3 on the left side indicates 3 carbon atoms.
- In a chemical equation, you can change coefficients, but you must never alter the subscripts.

6**Balance the hydrogen atoms next.** You have 8 on the left side. So you'll need 8 on the right side.

7**Balance the oxygen atoms.** **Assign a letter to each substance.** **Check the number of each element found on both sides, and set those equal to each other.** **olve this system of equations to get the numeric value for the coefficients.**Since there are more variables than equations, there are multiple solutions. You must find the one where every variable is in its smallest, non-fractional form.

- C
_{3}H_{8}+ O_{2}--> 4H_{2}O + 3CO_{2} - On the right side, you now added a 4 as the coefficient because the subscript showed that you already had 2 hydrogen atoms.
- When you multiply the coefficient 4 times by the subscript 2, you end up with 8.
- The other 6 atoms of Oxygen come from 3CO
_{2}.(3x2=6 atoms of oxygen+ the other 4=10)

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- Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. You now have 4 oxygen atoms in the water molecules and 6 oxygen atoms in the carbon dioxide molecules. That makes a total of 10 oxygen atoms.
- Add a coefficient of 5 to the oxygen molecule on the left side of the equation. You now have 10 oxygen atoms on each side.
- C
_{3}H_{8}+ 5O_{2}--> 4H_{2}O + 3CO_{2}. - The carbon, hydrogen, and oxygen atoms are balanced. Your equation is complete.

Algebraic Balance

1 **Write down the given equation.** For this example, we will use:

- PCl
_{5}+ H_{2}O --> H_{3}PO_{4}+ HCl

**a**PCl_{5}+**b**H_{2}O -->**c**H_{3}PO_{4}+**d**HCl

**a**PCl_{5}+**b**H_{2}O -->**c**H_{3}PO_{4}+**d**HCl- On the left side, there are 2
**b**atoms of hydrogen (2 for every molecule of H_{2}O), while on the right side, there are 3**c**+**d**atoms of hydrogen (3 for every molecule of H_{3}PO_{4}and 1 for every molecule of HCl). Since the number of atoms of phosphorus has to be equal on both sides, 2**b**must be equal to 3**c**+**d**. - Do this for every element.
- P:
**a**=**c** - Cl: 5
**a**=**d** - H: 2
**b**=3**c**+**d**

- P:

- To quickly do this, take on variable and assign a value to it. Let's take b=1. Then start solving the system of equations to get the following values:
- a=1/4
- b=1
- c=1/4
- d= 5/4

- Multiply everything by 4 to get the smallest, non-fractional solution.
- a=1
- b=4
- c=1
- d= 5

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