how to subtract 5ab from 11ab.
When 5a2b+10b2c2−21ab+32 is subtracted from 50−20b2c2−4bc−ac−5ab, we get
Subtract: (i) 5ab+4ac−6a+15c−15 from 10ab+22bc−13a−14b−16c−24 (ii) 5a2b+10b2c2−10b2c−21ab+32 from 50−20b2c2−4bc−ac−5ab. [2 MARKS]