Question

How tofin roots of a quadratic equation when it's x–co—efficient is an odd number explain it with an example

Answer 1

Let's assume a quadratic equation where the co-efficient of x is an odd number:
x2−5x+6=0

Now, we have to find the roots of the equation x2−5x+6=0


x2−5x+6
Splitting the middle term:
⇒x2−2x−3x+6=x(x−2)−3(x−2)






⇒(x−2)(x−3)=0⇒(x−2)=0or(x−3)=0⇒x=2,3
So the roots of the equation are 2 and 3

i hope this clears your doubt.

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