how will i unders†an d that △ H of a given reaction is +ve or -ve?

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2 O_{3} (g) \to 3 O_{2} (g), △ H

△ S

△ G

For a spontaneous reaction $△$ G, equilibrium constant (K) and $E_{c e l l}^{\circ}$ will be respectively:

(1 + i)^{n}

\begin{matrix} List - I & List - II (P) & Chloroform-methyl alcohol & (1) & Enthalpy change +ve (Q) & Methyl alcohol-ethyl alcohol & (2) & Enthalpy change -ve (R) & Ethyl alcohol-water & (3) & Entropy change +ve (S) & Water-nitric acid & (4) & Change in volume, Δ V = + v e (5) & Change in volume, Δ V = - v e \end{matrix}

α - D - (+)

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