How will the magnitude of magnification change if an object placed at the center of curvature is moved away from the mirror?

decreases

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increases

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remains constant

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magnification reaches infinity

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Solution

The correct option is A
decreases

(1)

(2)

(3)

As an object moves away from the mirror, the height of the image decreases, as shown in the figure.

Magnification = $\frac{h e i g h t o f i m a g e}{h e i g h t o f o b j e c t}$ .

As the height of the image decreases, the magnitude of magnification decreases.

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