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Byju's Answer

Standard XII

Chemistry

Activation Energy

How will the ...

Question

How will the rate $r = k [S O_{2}] [O_{2}]$ of reaction, $2 S O_{2} + O_{2} ⟶ 2 S O_{3}$ , change if the volume of the reaction vessel is tripled?

It will be

\frac{1}{3}

rd of its initial value

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It will be

3

times of its initial value

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It will be

9

times of its initial value

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It will be

\frac{1}{9}

th of its initial value

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Solution

The correct option is D It will be $\frac{1}{9}$ th of its initial value
First we have to find order of reaction
So order of reaction is sum of power of reactent concentration in rate equation
So order = 1+1 =2
Now second order reaction so

Answer will be D

Suggest Corrections

Similar questions

Q. If the volume of the vessel in which the reaction

2 N O + O_{2} ⟶ {2 N O}_{2}

is occurring is diminished to 1/3rd of its initial volume. The rate of the reaction will be increased by:

Q. Given 2NO

_{(g)}

+ O

_{2 (g)}

\to

2NO

_{2 (g)}

; rate = k

[N O]^{2}

[O_{2}

]

^{1}

. By how many times does the rate of the reaction change when the volume of the reaction vessel is reduced to 1/3

^{r d}

of its original volume? Will there be any change in the order of the reaction?

Q. Given

2 N O + O_{2} \to 2 N O_{2}

rate

= K {[N O]}^{2} [O_{2}]

by how many times does the rate of reaction change when the volume of the reaction vessel is reduced to

{1 / 3}^{r d}

of its original volume? Will there be any change in the order of the reaction?

Q. Given

2 N O_{(g)} + O_{2 (g)} \to 2 N O_{2 (g)}

; rate =

k [N O]^{2} [O_{2}]^{1}

. By how many times of the rate of the reaction change when the volume of the reaction vessel is reduced to

1 / 3^{r d}

of its original volume? Will there be any change in order of the reaction?

Q. For gaseous reaction, rate

k [A] [B]

. If volume of container is reduced to

1 / 4

of initial, then the rate of reaction will be _____ times of initial.

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How will the rate r=k[SO2][O2] of reaction, 2SO2+O2⟶2SO3, change if the volume of the reaction vessel is tripled?

The correct option is D It will be 19th of its initial valueFirst we have to find order of reactionSo order of reaction is sum of power of reactent concentration in rate equationSo order = 1+1 =2Now second order reaction soAnswer will be D

How will the rate $r = k [S O_{2}] [O_{2}]$ of reaction, $2 S O_{2} + O_{2} ⟶ 2 S O_{3}$ , change if the volume of the reaction vessel is tripled?

The correct option is D It will be $\frac{1}{9}$ th of its initial value
First we have to find order of reaction
So order of reaction is sum of power of reactent concentration in rate equation
So order = 1+1 =2
Now second order reaction so

Answer will be D