How will the reading of ammeter change if the key K is closed ?

Increase

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Decrease

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Remains same

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Information insufficient

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Solution

The correct option is B Decrease
When K is closed, R_{eq} will increase so by $I = \frac{V}{R_{e q}}$ ,value of current will be decrease.
Hence option 'B' is correct.

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What is the reading of ammeter in the figure. Assume that the internal resistance of battery is zero and the key is closed?

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