Question

How will the temperature of $10.0g$ of iron change if $45J$ is added to the metal?
Iron has a specific heat of $0.45J/\left(g^{o}C\right)$.

• A. $+{20}^{o}C$
• B. $+{10}^{o}C$
• C. $+{100}^{o}C$
• D. $+1^{o}C$

Answer 1

The correct option is B $+{10}^{o}C$

$Q=nC△T$

$Q=45J$ ; $n=10.0g$ ; $C=0.45J/g^{o}C$

Therefore, $45=nC△T$

$\Rightarrow \frac{45}{10.0\times 0.45}=△T$

$\Rightarrow 10=△T$