Step 1: Compute how 150 can be expressed 150o=180o−30o 30 degrees is half of 60 degrees which is an angle of equilateral triangle
Step 2: Draw a line segment AB Step 3: Choose a point C on AB and with BC as radius and centre as C, draw an arc. Again, with same radius but centre as B, draw another arc such that it cuts the previous arc at D. Now as BC=CD=BD, hence angle DCB would be 60o Step 4: Draw an arc with centre as D and radius as BC. Draw another arc with same radius but centre as B such that it cuts the previous arc at E. This will make EC the bisector of the angle BCD. Hence angle BCE is 30o So, angle ACE of 150 degrees is constructed