Question

How will you convert butan-2-one to propanoic acid?

• A. Tollen's reagent
• B. Fehling's solution
• C. $$I_2/NaOH/H^{+}$$
• D. $$NaI/NaOH/H^{+}$$

Answer 1

The correct option is C $$I_2/NaOH/H^{+}$$

Iodoform reaction is used for the given conversion.
Iodoform reaction is a chemical reaction in which a methyl ketone is oxidized to a carboxylate by reaction with aqueous $NaOH$ and $I_2$ which on hydrolysis produces carboxylic acid. The reaction also produces iodoform $\left(CH{I}_3\right)$, a yellow solid which may precipitate from the reaction mixture.
Ketone don't respond to Fehling and Tollen's reagent. Hence option c is correct.