How will you make the following equation linear- 5-x-1-1-y-2-26-x-1-3-y-2-1

The correct option is A Substitute 1/x 1 as p and 1/y 2 as q If we substitute 1/x 1as p and 1/y 2 as q in the given equations. We get the equations as 5p ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Equations Reducible to a Pair of Linear Equations in Two Variables

How will you ...

Question

How will you make the following equation linear?

$\frac{5}{x - 1}$ + $\frac{1}{y - 2}$ = 2

$\frac{6}{x - 1}$ - $\frac{3}{y - 2}$ = 1

Substitute 1/x-1 as p and 1/y-2 as q

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

substitute x=x+1 and y=y+2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The equation is already linear

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
Substitute 1/x-1 as p and 1/y-2 as q

If we substitute $\frac{1}{x - 1}$ as p and $\frac{1}{y - 2}$ as q in the given equations. We get the equations as

5p + q = 2

6q - 3q = 1

Now we can see that the equation is linear.

Suggest Corrections

Similar questions

How will you make the following equations linear?

$\frac{5}{x - 1}$ + $\frac{1}{y - 2}$ = 2

$\frac{6}{x - 1}$ - $\frac{3}{y - 2}$ = 1

How will you make the following equations linear?
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2$
$\frac{6}{x - 1} + \frac{3}{y - 2} = 1$
(where $x \neq 1 a n d y \neq 2)$

How will you make the following equations linear?
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2$
$\frac{6}{x - 1} + \frac{3}{y - 2} = 1$
(Where $x \neq 1, y \neq 2)$

Q. How will you make the following equations linear?

\frac{5}{x - 1} + \frac{1}{y - 2} = 2

\frac{6}{x - 1} + \frac{3}{y - 2} = 1

(Where

x \neq 1, y \neq 2)

What will you substitute to make the following equation a linear equation

$\frac{1}{x}$ + $\frac{3}{y}$ = 1

Join BYJU'S Learning Program

How will you make the following equation linear? 5x−1 + 1y−2 = 2 6x−1 - 3y−2 = 1

The correct option is A Substitute 1/x-1 as p and 1/y-2 as q If we substitute 1x−1as p and 1y−2 as q in the given equations. We get the equations as 5p + q = 2 6q - 3q = 1 Now we can see that the equation is linear.

How will you make the following equation linear?

$\frac{5}{x - 1}$ + $\frac{1}{y - 2}$ = 2

$\frac{6}{x - 1}$ - $\frac{3}{y - 2}$ = 1

The correct option is A
Substitute 1/x-1 as p and 1/y-2 as q

If we substitute $\frac{1}{x - 1}$ as p and $\frac{1}{y - 2}$ as q in the given equations. We get the equations as

5p + q = 2

6q - 3q = 1

Now we can see that the equation is linear.