Question

How will you make the following equation linear?

$\frac{5}{x-1}$ + $\frac{1}{y-2}$ = 2

$\frac{6}{x-1}$ - $\frac{3}{y-2}$ = 1

• A. Substitute 1/x-1 as p and 1/y-2 as q
• B. substitute x=x+1 and y=y+2
• C. The equation is already linear
• D. None of the above

Answer 1

The correct option is A

Substitute 1/x-1 as p and 1/y-2 as q

If we substitute $\frac{1}{x-1}$as p and $\frac{1}{y-2}$ as q in the given equations. We get the equations as

$5p+q=2$

$6q-3q=1$

Now we can see that the equation is linear.