Question

How will you make the following equations linear?
$\frac{5}{x-1}+\frac{1}{y-2}=2$
$\frac{6}{x-1}+\frac{3}{y-2}=1$
(Where $x\ne 1,y\ne 2)$

• A. Substitute $\frac{1}{x-1}$ as p and $\frac{1}{y-2}$ as q
• B. Subsitute $\frac{1}{x-1}$ as $\frac{1}{p}and\frac{1}{y-2}$ as $\frac{1}{q}$
• C. Substitute $x=X+1$ and $y=Y+2$
• D. The equation is already linear

Answer 1

The correct option is A Substitute $\frac{1}{x-1}$ as p and $\frac{1}{y-2}$ as q

If we substitute $\frac{1}{x-1}$ as p and $\frac{1}{y-2}$ as q in the given equations. (As $x\ne 1,y\ne 2)$
We get the equations as
$5p+q=2$
$6q-3q=1$
Now we can see that the equations are linear.