Question

How will you make the following equations linear?

$\frac{5}{x-1}$ + $\frac{1}{y-2}$ = 2

$\frac{6}{x-1}$ - $\frac{3}{y-2}$ = 1

• A. Substitute 1/(x-1) as p and 1/(y-2) as q
• B. substitute x = x+1 and y = y+2
• C. The equation is already linear
• D. None of the above

Answer 1

The correct option is A

Substitute 1/(x-1) as p and 1/(y-2) as q

If we substitute $\frac{1}{x-1}$as p and $\frac{1}{y-2}$ as q in the given equations, we get

5p + q = 2

6q - 3q = 1

Now we can see that the equations are linear.