How will you obtain? (Give chemical equations only)
(i) Sulphuric acid from sulphur
(ii) Phosphine from white phosphorus.

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Solution

(i) Sulphuric acid from sulphur by contact process
$S (s) + O_{2} (g) \to S O_{2} (g)$
$2 S O_{2} (g) + O_{2} (g) V_{2} O_{5} - -- \to 2 S O_{3} (g) Δ H = - 196.6$ kJ
$S O_{3} (g) + H_{2} S O_{4} (l) \to H_{2} S_{2} O_{7} (l)$
$H_{2} S_{2} O_{7} (l) + H_{2} O (l) \to 2 H_{2} S O_{4} (a q)$
(ii) Phosphine from white phosphorus.
$P_{4} + 3 N a O H + 3 H_{2} O \to P H_{3} + 3 N a H_{2} P O_{2}$

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How will you obtain? (Give chemical equations only)(i) Sulphuric acid from sulphur(ii) Phosphine from white phosphorus.

(i) Sulphuric acid from sulphur by contact processS(s)+O2(g)→SO2(g)2SO2(g)+O2(g)V2O5−−−→2SO3(g)ΔH=−196.6 kJSO3(g)+H2SO4(l)→H2S2O7(l)H2S2O7(l)+H2O(l)→2H2SO4(aq)(ii) Phosphine from white phosphorus.P4+3NaOH+3H2O→PH3+3NaH2PO2

How will you obtain? (Give chemical equations only)
(i) Sulphuric acid from sulphur
(ii) Phosphine from white phosphorus.