How will you obtain :
(i) Formic acid from Acetic acid
(ii) Acetaldehyde from Acetylene.

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Solution

(i) Formic acid from Acetic acid
$C H_{3} C H_{2} C O O H + 4 [H] N H_{3} - -- \to C H_{3} C O O N H_{4} △ - \to C H_{3} C H_{2} C H_{2} O H$
$B r_{2} / K O H - ----- \to C H_{3} N H_{2} H O N O - --- \to C H_{3} O N O H_{2} O - -- \to H e a t$
$C H_{3} O H [O] - \to H C H O [O] - \to H C O O H F o r m i c a c i d$
(ii) Acetaldehyde from Acetylene :
$C H_{3} C \equiv C H + H_{2} O 1 % H g^{2 +}, 42 % H^{2 +} - ---------- \to 60^{o} C \begin{matrix} C H_{3} C = C H_{2} \to C H_{3} C O C H_{3} | O H \end{matrix}$

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