How will you obtain the following from Phenol (give equation):
(i) 2, 4, 6 Trinitrophenol, (ii) 2, 4, 6 Tribromophenol, (iii) Benzene, (iv) Ortho and Para-Cresol.

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Solution

(i) $2, 4, 6 - T r i n i t r o p h e n o l$ :
$P h e n o l$ on nitration with nitrating mixture ( $H N O_{3} / H_{2} S O_{4}$ ) gives $2, 4, 6 - T r i n i t r o p h e n o l$ which is also called $p i c r i c a c i d$ .
(ii) $2, 4, 6 - T r i b r o m o p h e n o l$ :
$P h e n o l$ on treatment with $b r o m i n e w a t e r$ gives precipitate of $2, 4, 6 - T r i b r o m o p h e n o l$ .
(iii) $B e n z e n e$ :
When $p h e n o l$ is heated with $z i n c d u s t$ it gives $b e n z e n e$ .
(iv) $O r t h o a n d P a r a - C r e s o l$ :
When $P h e n o l$ is treated with $C H_{3} - C l / A l C l_{3}$ , it undergoes Friedel Craft's alkylation to form a mixture of $o r t h o a n d p a r a - c r e s o l$

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How will you obtain the following from Phenol (give equation):(i) 2, 4, 6 Trinitrophenol, (ii) 2, 4, 6 Tribromophenol, (iii) Benzene, (iv) Ortho and Para-Cresol.

How will you obtain the following from Phenol (give equation):
(i) 2, 4, 6 Trinitrophenol, (ii) 2, 4, 6 Tribromophenol, (iii) Benzene, (iv) Ortho and Para-Cresol.