Question

How will you prepare isopropyl alcohol from propene?

Answer 1

$C{H}_3-CH=C{H}_2+\underset{conc}{H_{2}S{O}_4}\to C{H}_3-\underset{OS{O}_{2}OH}{\underset{|}{CH}}-C{H}_3\underset{Boil}{\overset{H_{2}O}{\to }}C{H}_3-\underset{OH}{\underset{|}{CH}}-C{H}_3$