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Question

How will you separate a mixture containing chalk, iodine and sodium chloride?


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Solution

Separating a mixture of chalk or Calcium carbonate (CaCO3), Iodine (I2) and Sodium chloride (NaCl)

Step-1: Separation of iodine

  • The principle used in this step is that iodine is sublimable whereas chalk and sodium chloride is not.
  • Subject the mixture to sublimation in the china dish.
  • The process of conversion of a substance from a solid state into gaseous state on heating directly without converting into a liquid state is called sublimation.
  • It is observed that iodine will convert from solid to vapour state and leave the mixture.
  • Iodine(s)CoolHeatIodine(g)
  • On cooling of the vapours, iodine can be attained back in the solid state as a sublimate.
  • The residue of chalk and sodium chloride is left in the china dish.

Step-2: Separation of chalk

  • Water (H2O) is added to the residue obtained in step-1.
  • The principle involved in this step is that sodium chloride is soluble in water whereas chalk is not.
  • On addition of water to it, sodium chloride gets dissolved in it but chalk remains undissolved.
  • This mixture is left for sometime to settle down.
  • This process of settling down of the particles that remain undissolved is known as sedimentation.
  • Water containing dissolved sodium chloride is called supernatant and separated by the process called decantation.
  • The residue of chalk is left behind in the beaker separating chalk from the mixture.

Step-3: Separation of sodium chloride

  • The supernatant comprising sodium chloride dissolved in water is subjected to evaporation.
  • The separation of sodium chloride from water is based on the fact that water can evaporate whereas sodium chloride can not.
  • As water gets evaporated, solid powdered sodium chloride is left behind.

Thus, the said mixture can be separated using a combination of more than one method of separation.


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