how would the magnetic field produced by a long current carrying wire will change, if current through it is doubled and the length of the wire is halved

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$T h e f o r c e e x p e r i e n c e d b y a c u r r e n t c a r r y i n g c o n d u c t o r i s g i v e n b y, F = B I L \sin θ . S o B = \frac{F}{I L \sin θ}, w h e n c u r r e n t i s 2 I a n d l e n g t h i s L / 2 t h e n, B = \frac{F \times 2}{2 I L \sin θ} = \frac{F}{I L s i n θ}, t h u s f r o m t h i s c h a n g e, w e c o m e t o k n o w t h a t t h e v a l u e o f m a g n e t i c f i e l d r e m a i n s u n c h a n g e d .$

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