How would you relate the new frequency to original one when an X-ray photon collides with an electron and bounces off ?

Is lower than its original frequency

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Is same as its original frequency

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Is higher than its original frequency

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Depends upon the electrons frequency

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Solution

The correct option is A Is lower than its original frequency
From Scattering Formula
$λ^{'} - λ = \frac{G}{M_{e} c} (1 - c o s θ)$
We can see, $λ^{'} > λ$
So $v^{'} < v$

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How would you relate the new frequency to original one when an X-ray photon collides with an electron and bounces off ?

The correct option is A Is lower than its original frequency From Scattering Formulaλ′−λ=GMec(1−cosθ)We can see, λ′>λSo v′<v

The correct option is A Is lower than its original frequency
From Scattering Formula
$λ^{'} - λ = \frac{G}{M_{e} c} (1 - c o s θ)$
We can see, $λ^{'} > λ$
So $v^{'} < v$