Question

$H{S}^{-}+O{H}^{-}\to S^{2-}+H_{2}O$
In the system indicated by the equation above, brosnted acids are:

• A. $H{S}^{-}and{H}_{2}O$
• B. $H{S}^{-}and{S}^{2-}$
• C. $H{S}^{-}andO{H}^{-}$
• D. $S^{2-}and{H}_{2}O$
• E. $O{H}^{-}and{H}_{2}O$

Answer 1

The correct option is A $H{S}^{-}and{H}_{2}O$

Since bronsted acids, are proton donors, So ${HS}^{-}$ and $H_{2}O$ can act as acids

to give proton as $(S^{2-}+H^{+})$ and $({OH}^{-}+H^{+})$ respectively.