Question

Hundred ML of an aqueous solution contains 6.023 $\times {10}^{21}$ Solute moleculesThe solution is diluted 1 L The number of solute molecules present in 10ml of dilute solution is

Answer 1

The solution is diluted to 1L or 1000 ml.

Dilution refers to the process of adding additional solvent to a solution to decrease its concentration. This process keeps the amount of solute constant, but increases the total amount of solution, thereby decreasing its final concentration.

100 ml solution diluted to 1 liters (1000) ml contains 6.023$\times {10}^{21}$ solute molecules.

No of molecules present in 10 ml = $\frac{10\times 6.023\times {10}^{21}}{1000}=6.023\times {10}^{19}molecules$