Question

Hussain has 5 red, 3 blue and 2 green socks. If a sock is drawn at random, match the following probabilities.

• A. $\frac{3}{10}$
• B. $\frac{1}{2}$
• C. $\frac{1}{5}$

Answer 1

Number of red socks= $5$
Number of blue socks= $3$
Number of green socks= $2$

$\therefore$Total number of socks= $5+3+2=10$

Now, the probability of drawing a red sock:
$\underset{–}{\text{P(Red)}=\frac{\text{Number of red socks}}{\text{Total number of socks}}=\frac{5}{10}=\frac{1}{2}}$

Next, the probability of drawing a blue sock:
$\underset{–}{\text{P(Blue)}=\frac{\text{Number of blue socks}}{\text{Total number of socks}}=\frac{3}{10}}$

And, the probability of drawing a green sock:
$\underset{–}{\text{P(Green)}=\frac{\text{Number of green socks}}{\text{Total number of socks}}=\frac{2}{10}=\frac{1}{5}}$