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Question

HX is a weak acid (Ka=105). It forms a salt NaX (0.1M) on reacting with caustic soda. What is the percentage of degree of hydrolysis (h) of NaX ?

A
0.01
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B
0.1
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C
0.001
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D
None of the above
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Solution

The correct option is A 0.01
Given, Ka=105, [NaX]=0.1 M
According to question, NaX is a mixture of weak acid and strong base.
Therefore X only undergoes hydrolysis
at eqb. XCCh+H2OKaHXCh+OHCh
'h' is hydrolysis constant and 'C' is concentration
Kh=[HX][OH][X][H2O]
we know,
Kh=KwKa=1014105
Kh=109
we know
h=KhC=1090.1=108
h=104
degree of hydrolysis (h)=104
percentage degree of hydrolysis=104×100=0.01

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