wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

HX is a weak acid (Ka=105). It forms a salt NaX having concentration of 0.1M, on reacting with caustic soda. What is the degree of hydrolysis (h) of the salt?

A
104
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
102
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
106
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 104
Given, Ka=105, [NaX]=0.1 M
According to question, NaX is a salt of weak acid and strong base.
Therefore X only undergoes hydrolysis.
at equilibrium we have,
XCCh+H2OKaHXCh+OHCh


'Kh' is hydrolysis constant and 'C' is concentration
Kh=[HX][OH][X]
we know,
Kh=KwKa=1014105
Kh=109
we know
h=KhC=1090.1=108
h=104
degree of hydrolysis (h)=104
and also
percentage degree of hydrolysis=104×100=0.01

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon