Hybrid orbital having maximum p - character is:

s p^{3} d

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s p^{3}

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s p

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s p^{3} d^{2}

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Solution

The correct option is B $s p^{3}$
In $s p^{3}$ hybridization, 'p' character is $\frac{3}{4} i . e .,$ 75% (because of 3 p orbitals and total 4 orbitals).

Option B is correct.

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Similar questions

What is the hybridization of P in $P C l_{5} (s)$ ?

X e F_{2}, X e F_{3}^{+}, X e F_{4}, X e F_{6}

${s p}^{2}$ hybrid orbitals have equal s and p character.

P C l_{5} (s)

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

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