Question

Hybridisation of $C_2$ and $C_3$ of $H_{3}C-CH=C=CH-{CH}_3$ are :

• A. $sp,{sp}^3$
• B. ${sp}^2,sp$
• C. ${sp}^2,{sp}^2$
• D. $sp,sp$

Answer 1

The correct option is B ${sp}^2,sp$

$\stackrel{1}{C}{H}_3-\stackrel{2}{\underset{\uparrow {sp}^2}{C}}H=\stackrel{3}{\underset{\uparrow sp}{C}}=\stackrel{4}{C}H-\stackrel{5}{C}{H}_3$

Hybridisation of carbon atoms in $H_{3}C-CH=C=CH-C{H}_3$ are $s{p}^2$ and $sp$.

$\therefore$ option B is correct.