Question

Hybridisation of carbon atom in $C{H}_3^{+}$ is:

• A. $sp$
• B. $s{p}^2$
• C. $s{p}^3$
• D. $s{p}^3$d

Answer 1

The correct option is B $s{p}^2$

In $C{H}^{3+}$ the one valency is still free, so the electrons taking part in bond forming are contained in $2s,2p_x,2p_y$ but $2p_z$ don't have any electrons so it is not participating in bonding.So hybridization is $s{p}^2$ as $2p$ orbitals and $1s$ orbital are taking part in hybridization.