Hybridisation of carbon atoms in diamond is:

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is B $s p^{3}$
In diamond $C$ is $s p^{3}$ hybridised and bonded to four other carbon atoms using covalent bonds.

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C (1) H_{2} = C (2) H - C (3) \equiv C H

A l H_{3}

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(C_{3} H_{4}),

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

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