Question

Hybridisation of iodine in iodine hepta fluoride molecule is:

• A. $s{p}^3{d}^3$
• B. $s{p}^{3}d$
• C. $s{p}^3{d}^2$
• D. $ds{p}^2$

Answer 1

The correct option is A $s{p}^3{d}^3$

Hybridization of iodine in iodine hepta fluoride molecule is $s{p}^3{d}^3$. In iodine, one s, three p and three d orbital hybridize to form $s{p}^3{d}^3$ hybrid orbitals.