Hybridisation of N atom in $H N O_{2}$ and $H N O_{3}$ is $s p^{2}$ .
If true enter 1, else enter 0.

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Solution

A single bond is equal to a bond
A double bond is 1 bond and 1 bond
$H y b r i d i s a t i o n = N u m b e r o f s i g m a b o n d s + n u m b e r o f l o n e p a i r s l o n e p a i r s$
$H N O_{2}$ :
H-O-N=O
Hybridisation of N-atom in $H N O_{2}$ and $H N O_{3}$ is $s p^{2}$ . if t
so the hybridization around Central N is
1 bond and 2 bond

The
Nitrogen bonds in two areas with an unpaired shared of electrons.
Multiple bonds are considered to be one bonding area. So the
hybridization would be sp^2.
Hence option 1 is correct.

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