Question

Hybridization is the chemist's attempt to explain the observed molecular shape by constructing hybridized atomic orbitals with the appropriate inter orbital angles. The molecule for which deviation from a normal bond angle is observed, $VSEPR$ theory suggests electron pair repulsive interaction ($lp-lp>lp-bp>bp$). While from hybridization point of view that is a departure from normal hybridization because the angle between any equivalent hybrid orbitals determines the fraction of s and p characters of the hybrid and vice-versa.

In which species number of lone pairs on iodine and number of d-orbitals used in hybridization by iodine are the same?

• A. ${IC{l}_2}^{+}$
• B. ${IC{l}_2}^{-}$
• C. $I{F}_7$
• D. ${IC{l}_4}^{-}$

Answer 1

The correct option is D ${IC{l}_4}^{-}$

So in $IC{l}_4^{-}$ The number of lone pairs are $2$ and the d- electrons used in hybridisation are $2$.

Hence option D is correct.