Hybridization of $2^{n d}$ carbon in $C H_{2} = C H - C H_{3}$ is

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is B $s p^{2}$
Solution:
$C^{1} H_{2} = C^{2} H - C^{3} H_{3}$

Started assigning numbering from left carbon. $1^{s t}$ and $2^{n d}$ carbon are $s p^{2}$ and $3^{r d}$ carbon is $s p^{3}$ hybridized.
So option B is correct answer.

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Hybridization of 2nd carbon in CH2=CH−CH3 is

The correct option is B sp2Solution:C1H2=C2H−C3H3Started assigning numbering from left carbon. 1st and 2nd carbon are sp2 and 3rd carbon is sp3 hybridized.So option B is correct answer.

Hybridization of $2^{n d}$ carbon in $C H_{2} = C H - C H_{3}$ is

The correct option is B $s p^{2}$
Solution:
$C^{1} H_{2} = C^{2} H - C^{3} H_{3}$

Started assigning numbering from left carbon. $1^{s t}$ and $2^{n d}$ carbon are $s p^{2}$ and $3^{r d}$ carbon is $s p^{3}$ hybridized.
So option B is correct answer.