Hybridization of carbon in $C_{3} O_{2}$ is :

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is A $s p$
In $C_{3} O_{2}$ , each carbon forms 2 pi bond and 2 sigma bond, so each carbon is sp hybridized.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

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