Question

Hybridization of central atom is independent of the phase/state of the compound in case of:

• A. $Be{H}_2$
• B. $N_2{O}_5$
• C. $Xe{F}_6$
• D. $P{F}_5$

Answer 1

Answer: (D)

$P{F}_5$

A) Beryllium hydride is a monomer in a gaseous state with $sp$ hybridization and polymer in the solid state with $s{p}^3$ hybridization.

B) In gaseous state, each $N$ atom in $N_2{O}_5$ undergoes $s{p}^2$ hybridization. In solid state $N_2{O}_5$ is present in the form of $[N{O}_2{]}^{+}$ and $[N{O}_3{]}^{-}$ ions with $sp$ and $s{p}^2$ hybridization respectively.

C) $Xe$ atom in $Xe{F}_6$ in gaseous state is $s{p}^3{d}^3$ hybridized and in solid state it is $s{p}^3{d}^2$ hybridized.

D) The $P$ atom in $P{F}_5$ in solid as well as in gaseous state is $s{p}^{3}d$ hybridized.

Hence, option D is the correct answer.