Hybridization of tertiary carbon atom in isobutane is:

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is D $s p^{3}$
Alkanes have all $C$ in $s p^{3}$ hybridized state irrespective of their degree (primary, secondary, tertiary, quaternary)

Hence, option $C$ is correct.

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