Question

Hybridization, shape, and magnetic moment of $K_3\left[Co\right(C{O}_3{)}_3]$ are :

• A. $d^{2}s{p}^3$, octahedral, 4.9 B.M.
• B. $s{p}^3{d}^2$, octahedral, 4.9 B.M.
• C. $ds{p}^3$, square planar, 4.9 B.M.
• D. $s{p}^3$, tetrahedral, 4.9 B.M.

Answer 1

The correct option is B $s{p}^3{d}^2$, octahedral, 4.9 B.M.

$K_3\left[Co\right(C{O}_3{)}_3]$
+3 $d^6$ configuration
weak ligand so no pairing and high spin complex forms
so $s{p}^3{d}^2$ hybridization takes place and octahedral complex forms
Also as it have 4 unpaired electron so
magnetic moment
$\mu =\sqrt{n(n+2)}=4.9$ BM
n = no of unpaired electron