Hybridization state of beryllium atom in $B e C l_{2}$ molecule is $x$ . The type of hybridization changes to $y$ when $B e C l_{2}$ transforms to the solid state. Then $x, y$ are respectively:

s p, s p^{2}

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s p, s p^{3}

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s p^{2}, s p^{3}

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s p, s p

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Solution

The correct option is B $s p, s p^{3}$
R.E.F image
$s p,$ hybridsation
$B e C l_{2} (s),$ hybridisation is $s p^{3}$
$B e C l_{2} \to B e C l_{2} (s)$
sp hybridisation $s p^{3}$ hybrisiation

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

{s p}^{3}

{s p}^{2}

s p

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