Question

Hybridization state of carbon changes as follows.

$s{p}^3\to s{p}^2\to sp$, then the angles of hybrid orbitals will

• A. Remain unchanged
• B. Go on increasing
• C. Go on decreasing
• D. First increse then decrease

Answer 1

Answer: (B)

Go on increasing

When the hybridization state of carbon atom changes from $s{p}^3\to s{p}^2\to sp$ the angle between the hybridized orbitals increases progressively. The bond angles in $s{p}^3,s{p}^2,sp$ hybridisation are ${109.28}^o,{120}^{,}{180}^o$ respectively.

So bond angle goes on increasing with the increase in $s$ character from $s{p}^3\to s{p}^2\to sp$

Option B is correct.