Hydration energy
${Δ H}_{h y d r a} . (k J m o l^{- 1})$ Lattice energy
$Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499 LiCl-840
$N a^{+}$ -390 NaCl-776
$K^{+}$ -305 KCl-703
$C l^{-}$ -382
Maximum heat is absorbed in the dissolution of one mole of :

LiCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

NaCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

KCl

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

equally

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C KCl
Maximum heat is absorbed in the dissolution of one mole of KCl. It is equal to 16 kJ/mol.

$Δ H_{s o l} = Δ H_{h y d} - Δ H_{U} (k J / m o l)$
LiCl
$- 499 - 382 + 840 = - 41$
NaCl
$- 390 - 382 + 776 = 4$
KCl
$- 305 - 382 + 703 = 16$

Suggest Corrections

Similar questions

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382