Hydration energy
${Δ H}_{h y d r a} . (k J m o l^{- 1})$ Lattice energy
$Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499 LiCl-840
$N a^{+}$ -390 NaCl-776
$K^{+}$ -305 KCl-703
$C l^{-}$ -382
Which salt can be used to control humidity?

L i C l

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N a C l

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K C l

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None of these

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Solution

The correct option is B $L i C l$
$Δ H_{s o l u t i o n} = Δ H_{h y d r a t i o n} - Δ H_{l a t t i c e e n e r g y}$

$Δ H_{H y d r a t i o n} = Δ H_{h y d r a t i o n} (c a t i o n) + Δ H_{h y d r a t i o n} (a n i o n)$

$Δ H_{s o l u t i o n}$ $(L i C l) = - 499 - 382 + 840 = - 41 k J / m o l$
Similarly,
$Δ H_{s o l u t i o n} (N a C l) = - 4 k J / m o l$
$Δ H_{s o l u t i o n} (K C l) = + 16 k J / m o l$

As $Δ H_{s o l u t i o n} (L i C l)$ is highest so it will absorb water most easily and it can control humidity easily.

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Similar questions

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382