Hydration energy
${Δ H}_{h y d r a} . (k J m o l^{- 1})$ Lattice energy
$Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499 LiCl-840
$N a^{+}$ -390 NaCl-776
$K^{+}$ -305 KCl-703
$C l^{-}$ -382
Which salt has maximum heat of hydration?

LiCl

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

NaCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

KCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

LiCl and KCl equally

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A LiCl
As hydration energy is proportional to 1/cation size and as we move down the group, size increases so heat of hydration decreases.

$Δ H_{H y d r a t i o n} = Δ H_{h y d r a t i o n} (c a t i o n) + Δ H_{h y d r a t i o n} (a n i o n)$

Hence option A is correct.

Suggest Corrections

Similar questions

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382

Hydration energy ${Δ H}_{h y d r a} . (k J m o l^{- 1})$	Lattice energy $Δ H_{u} (k J m o l^{- 1})$
$L i^{+}$ -499	LiCl-840
$N a^{+}$ -390	NaCl-776
$K^{+}$ -305	KCl-703
$C l^{-}$ -382