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Byju's Answer
Standard XII
Chemistry
Stoichiometric Calculations
Hydrazine N...
Question
Hydrazine
(
N
2
H
4
)
is a rocket fuel which can be produced according to the following reaction:
C
l
N
H
2
+
2
N
H
3
→
N
2
H
4
+
N
H
4
C
l
When
1000
g of
C
l
N
H
2
is reacted with excess of
N
H
3
,
473
g of
N
2
H
4
is produced. What is the percentage yield of the reaction?
A
76.12
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B
67.21
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C
26.17
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D
16.72
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Solution
The correct option is
A
76.12
1
mole of
C
l
N
H
2
reacts to form
1
mole of
N
2
H
4
.
The molar mass of
C
l
N
H
2
is
35.5
+
14
+
2
=
51.5
g/mol
The molar mass of
N
2
H
4
is
2
(
14
)
+
4
=
32
g/mol
Thus,
51.5
g of
C
l
N
H
2
reacts to form
32
g of
N
2
H
4
.
Thus,
1000
g of
C
l
N
H
2
reacts to form
32
×
1000
51.5
=
621.36
g of
N
2
H
4
.
However, only
473
g of
N
2
H
4
are obtained.
Hence, the percentage yield of the reaction is
473
621.36
×
100
=
76.12
%
.
Therefore, option A is correct.
Suggest Corrections
0
Similar questions
Q.
Hydrazine
(
N
2
H
4
)
can be produced according to the following reaction:
C
l
N
H
2
+
2
N
H
3
→
N
2
H
4
+
N
H
4
C
l
. 1 kg of
C
l
N
H
2
is reacted with excess
N
H
3
, find the actual number of molecules of
N
2
H
4
produced if the percentage yield of the given reaction is 76%.
Q.
Hydrazine
(
N
2
H
4
)
can be produced according to the following reaction:
C
l
N
H
2
+
2
N
H
3
→
N
2
H
4
+
N
H
4
C
l
. 1 kg of
C
l
N
H
2
is reacted with excess
N
H
3
, find the actual number of molecules of
N
2
H
4
produced if the percentage yield of the given reaction is 76%.
Q.
In the following reaction, hydrazine is oxidised to
N
2
.
N
2
H
4
+
O
H
−
→
N
2
+
H
2
O
+
e
−
.
The equivalent mass of
N
2
H
4
(hydrazine) is:
Q.
Some rocket engines use a mixture of Hydrazine,
N
2
H
4
and Hydrogen peroxide,
H
2
O
2
as the propellant. The reaction is given by the following equation.
N
2
H
4
(
l
)
+
2
H
2
O
2
(
l
)
→
N
2
(
g
)
+
4
H
2
O
(
g
)
How much of the excess reactant remains unchanged when
0.705
m
o
l
of
N
2
H
4
is mixed with
17
g
of
H
2
O
2
?
Q.
0.32
g of
N
2
H
4
is dissolved in water to make up to a
1
L solution. The percentage of
N
2
H
4
that has reacted with water in this solution is:
(
K
b
(
N
2
H
4
)
=
4.0
×
10
−
6
)
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