Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is:

C H_{3} - C H_{3}

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C H_{2} = C H_{2}

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C H \equiv C H

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C H_{4}

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Solution

The correct option is C $C H_{4}$
$R - H + {B r}_{2} S u b s t i t u t i o n - --------- \to R - B r + H B r$
$2 R - B r + 2 N a w u r t z r e a c t i o n - ------------ \to R - R + 2 {N a}^{+} {B r}^{-}$
In substitution reaction alkanes produces alkyl bromides and in Wurtz reaction two alkyl halides are reacted with sodium $(N a)$ metal to form higher alkane.
Since after Wurtz reaction, the gaseous hydrocarbon has less than $4$ carbon atoms. So, $^{'} R^{'}$ should contain only $1$ carbon atom. So $A$ is ${C H}_{4}$ .

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