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Standard X

Mathematics

Method of Substitution to Find the Solution of a Pair of Linear Equations

Hydrochloric ...

Question

Hydrochloric acid solutions A and B have concentration of 0.5 N and 0.1 N respectively. The volume of solutions A and B required to make 2 litres of 0.2 N hydrochloric are

0.5 l of A + 1.5 l of B

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1.5 l of A + 0.5 l of B

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1.0 l of A + 1.0 l of B

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0.75 l of A + 1.25 l of B

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Solution

The correct option is A 0.5 l of A + 1.5 l of B
$N V = N_{1} V_{1} + N_{2} V_{2}$
$0.2 \times 2 = 0.5 x + 0.1 (2 - x)$
$0.4 = 0.5 x + 0.2 - 0.1 x$
$0.2 = 0.4 x$
$x = \frac{1}{2} L = 0.5 L$

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Hydrochloric acid solutions A and B have concentration of 0.5 N and 0.1 N respectively. The volume of solutions A and B required to make 2 litres of 0.2 N hydrochloric are

The correct option is A 0.5 l of A + 1.5 l of BNV=N1V1+N2V2 0.2×2=0.5x+0.1(2−x) 0.4=0.5x+0.2−0.1x 0.2=0.4x x=12L=0.5L

The correct option is A 0.5 l of A + 1.5 l of B
$N V = N_{1} V_{1} + N_{2} V_{2}$
$0.2 \times 2 = 0.5 x + 0.1 (2 - x)$
$0.4 = 0.5 x + 0.2 - 0.1 x$
$0.2 = 0.4 x$
$x = \frac{1}{2} L = 0.5 L$